linux下的sed命令的使用（查找替换字符串）

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

static void     test(void)
{
    char buffer[1024] = {0};
    sprintf(buffer,"sed -i 's/^.*%s.*$/%s/' %s","SSID",
            "SSID=112S0000003","RT2870AP.dat");
    printf("%s\n",buffer);
    system(buffer);

    memset(buffer,0,1024);
    sprintf(buffer,"sed -i 's/^.*%s.*$/%s/' %s","AuthMode",
            "AuthMode=","RT2870AP.dat");
    printf("%s\n",buffer);
    system(buffer);

    memset(buffer,0,1024);
    sprintf(buffer,"sed -i 's/^.*%s.*$/%s/' %s","EncrypType",
            "EncrypType=","RT2870AP.dat");
    printf("%s\n",buffer);
    system(buffer);

    memset(buffer,0,1024);
    sprintf(buffer,"sed -i 's/^.*%s.*$/%s/' %s","WPAPSK",
            "WPAPSK=","RT2870AP.dat");
    printf("%s\n",buffer);
    system(buffer);
}


int main(int argc,char *argv[])
{
    test();

    return 0;
}

测试结果：