HDU A + B Problem II 1002

A + B Problem II

#include <iostream>
#include <cstring>
#include <stdio.h>
#include <memory.h>
#include <string.h>

using namespace std;

char a[1000],b[1000],c[1000];

int main()
{
    int n;
    int an,bn;
    int p = 0;
    int i = 0;
    scanf("%d",&n);
    while(n--)
    {
        memset(a,0,sizeof(char)*1000);
        memset(b,0,sizeof(char)*1000);
        memset(c,0,sizeof(char)*1000);
        scanf("%s %s",a,b);
        an = strlen(a) - 1;
        bn = strlen(b) - 1;
        for(i = 0; an>=0||bn>=0; an--, bn--, i++)
        {
            if(an >= 0 && bn >= 0)
            {
                c[i] = a[an] + b[bn] - '0' + p;
            }
            if(an >= 0 && bn < 0)
            {
                c[i] = a[an] + p;
            }
            if(bn >= 0 && an < 0)
            {
                c[i] = b[bn] + p;
            }
            p = 0;
            if(c[i] > '9')
            {
                c[i] = c[i] - 10;
                p = 1;
            }
        }
        while(i--)
        {
            printf("%c",c[i]);
        }
        printf("\n");
    }
}

/*
#include<stdio.h>
#include<string.h>
int main()
{
    char a[1000],b[1000],c[1001];
    int i,j=1,p=0,n,n1,n2;
    scanf("%d",&n);
    while(n)
    {
        scanf("%s %s",a,b);
        printf("Case %d:\n",j);
        printf("%s + %s = ",a,b);
        n1=strlen(a)-1;
        n2=strlen(b)-1;
        for(i=0;n1>=0||n2>=0;i++,n1--,n2--)
        {
            if(n1>=0&&n2>=0)
                {c[i]=a[n1]+b[n2]-'0'+p;}
            if(n1>=0&&n2<0)
                {c[i]=a[n1]+p;}
            if(n1<0&&n2>=0)
                {c[i]=b[n2]+p;}
            p=0;
            if(c[i]>'9'){c[i]=c[i]-10;p=1;}
        }
        if(p==1){printf("%d",p);}
        while(i--)
        {printf("%c",c[i]);}
        j++;
        if(n!=1){printf("\n\n");}
        else {printf("\n");}
        n--;
    }
}
*/