抽象工厂模式

现在可以看到，想新来做一个菜系，只需新聘请一个厨师就可以了，多么完美，但是如果你想新增加一个菜就变得非常困难了。

#include

using namespace std;

//meat base
class baseMeat
{
    public:
        virtual void getMeat(){};
};

//braising meat
class braisingMeat:public baseMeat
{
    public:       
        void getMeat()
        {
            cout <<"this is braising meat\n";
        };
};

//steamed meat
class steamedMeat:public baseMeat
{
    public:
        void getMeat()
        {
            cout <<"this is steamed meat\n";
        };
};

//fish base
class baseFish
{
    public:
        virtual void getFish(){};
};

//braising fish
class braisingFish:public baseFish
{
    public:
        void getFish()
        {
            cout <<"this braising fish\n";
        };
};

class steamedFish:public baseFish
{
    public:
        void getFish()
        {
            cout <<"this is steamed fish\n";
        };
};

//factory base
class factoryBase
{
    public:
        virtual baseMeat *createMeat(){};
        virtual baseFish *createFish(){};
};

class braisingFactory:public factoryBase
{
    public:
        baseMeat *createMeat()
        {
            return new braisingMeat;
        };

        baseFish *createFish()
        {
            return new braisingFish;
        };
};

class steamedFactory:public factoryBase
{
    public:
        baseMeat *createMeat()
        {
            return new steamedMeat;
        };
        baseFish *createFish()
        {
            return new steamedFish;
        };
};

int main()
{
    factoryBase *factory = new braisingFactory;
    baseMeat *meat = factory->createMeat();
    baseFish *fish = factory->createFish();
    meat->getMeat();
    fish->getFish();
    delete factory;
    delete meat;
    delete fish;

    factory = new steamedFactory;
    meat = factory->createMeat();
    fish = factory->createFish();
    meat->getMeat();
    fish->getFish();

    return 0;
}

适用性：

一个系统要独立于它的产品的创建、组合和表示时
一个系统要由多个 产品系列中的一个来配置时
当你要强调一个系列相关的产品对象的设计以便进行联合使用时
当你提供一个产品类库，而只想显示它们的接口而不是实现时。