不使用库函数，将int→char *

#include <stdio.h>

char *int2str(int value, char *string, int radix)
{
    int v = 0, x = 0, i =0;
    char tmp[33] = {0};
    char *pStr = string;

    /* save sign */
    if(value < 0)
    {
        value = -value;

        *pStr++ = '-';
    }

    /* calc & save to tmp[] */
    v = value;
    while(v > 0)
    {
        x = v % radix;
        v = v / radix;

        if(x < 10)
        {
            tmp[i++] = x + '0';
        }
        else
        {
            tmp[i++] = x + 'a' - 10;
        }
    }
    --i;

    while(i >= 0)
    {
        *pStr++ = tmp[i--];
    }

    return string;
}

int main()
{
    char *ret = NULL;
    char str1[10] = {0};
    char str2[10] = {0};

    ret = int2str(-12, str1, 10);
    ret = int2str(12, str2, 16);

    return 0;
}