不用分支、跳转语句选出两数中较大的一个

汇编语言实现：

xor ebx, ebx
cmp eax, [input1]
setg bl           ; if (eax > [input1]) set bl = 0x01;
neg ebx           ; neg 1 = 0xffffffff. neg is the arithmatich 'negate' operation
mov ecx, ebx
and ecx, eax
not ebx           ; not 0 = 0xffffffff, not 0xffffffff = 0
and ebx, [input1]
or ecx, ebx

C语言实现完全就是从汇编翻译过来的，^_^

#include

int
main() {
  int a, b, flag, result;
  scanf("%d %d", &a, &b);
  flag = a > b;
  flag = -flag;
  result = flag & a;
  result |= ((~flag) & b);
  printf("\nbigger one: %d\n", result);
  return 0;
}