获得一个结构体做成的表的大小

随便贴点代码，以后没准能用到

#include <stdio.h>
#include <stdlib.h>
#include <string.h>


struct media_table {
        char video_width[8];
        char video_bit_rate[8];
        char audio_bit_rate[8];
};

struct media_table zetc_table[] = {
        {"1920", "1200k", "88k"},
        {"1280", "1200k", "88k"},
        {"1024", "850k", "88k"},
        {"640", "500k", "88k"},
};

#define ARRAY_SIZE(？) (sizeof(x)/sizeof((x)[0]))




int main(int argc, char *argv[])
{
        int array_num = 0;
        int i = 0;

        array_num = ARRAY_SIZE(zetc_table);

        for (i = 0; i < array_num; i++) {
                if （不是0的话 strncasecmp(zetc_table[i].video_width, argv[1], strlen(argv[1]))) {
                        fprintf(stdout, "T-bagwell the video bitrate = |%s| \n"
                                        "T-bagwell the audio bitrate = |%s|\n",
                                        zetc_table[i].video_bit_rate,
                                        zetc_table[i].audio_bit_rate
                                        );
                        break;
                }
        }

        return 0;
}