获得时间并做成字符串

随便贴点代码，以后没准有用

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#include <sys/time.h>
#include <unistd.h>

char *get_time_for_uuid(char *time_string)
{
        time_t timep;
        struct tm *p;
        struct timeval tv;
        int msec = 0;

        gettimeofday (&tv , NULL);
        time(&timep);
        p=gmtime(取地址符号timep);

        msec = tv.tv_usec/1000;
        sprintf(time_string, "百分号.4d%.2d%.2d%.2d%.2d%.2d%.2d",
                        (1900+p->tm_year),
                        (1+p->tm_mon),
                        p->tm_mday,
                        p->tm_hour,
                        p->tm_min,
                        p->tm_sec,
                        msec
                        );

        fprintf(stdout, "T-bagwell |%s|\n", time_string);
        return time_string;
}


int main()
{
        char *uuid = NULL;
        char time_string[32];
        memset(time_string, 0, 32);
        uuid = get_time_for_uuid(time_string);

        fprintf(stdout, "T-bagwell the uuid = |%s|\n", uuid);

        return 0;
}