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分类: Python/Ruby

2015-04-24 03:58:19


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  1. CHINESE_DIGITS = '零一二三四五六七八九'
  2. CHINESE_UNITS = ('','十','百','千','万', '亿')
  3. TRANS = str.maketrans('一二三四五六七八九十百千', '壹贰叁肆伍陆柒捌玖拾佰仟')

  4. __all__ = ["digit2Chinesexx", "digit2ChinexeDX"]

  5. def digit2Chinesexx(num):
  6.     """Return the small Chinese Charactors string of a num."""
  7.     num = int(num)
  8.     res = tslt_le16(abs(num))
  9.     if num < 0:
  10.         res = '负' + res
  11.     return res

  12. def digit2ChineseDX(num):
  13.     """Return the big Chinese Charactors string of a num."""
  14.     return digit2Chinesexx(num).translate(TRANS)


  15. def tslt_le4(intnum):
  16.     lststr = list(str(intnum).zfill(4)[::-1])
  17.     units = tuple(CHINESE_UNITS[i] if lststr[i] != '0' else '' for i in range(4))

  18.     for i in range(3):
  19.         if lststr[i+1] == '0' and lststr[i] == '0':
  20.             lststr[i] = ''
  21.     else:
  22.         if lststr[3] == '0':
  23.             lststr[3] = ''

  24.     for i in range(4):
  25.         if lststr[i]:
  26.             lststr[i] = CHINESE_DIGITS[int(lststr[i])]

  27.     result = ''.join(lststr[i] + units[i] for i in range(3, -1, -1))

  28.     result = result[:-3].replace('二', '两') + result[-3:]

  29.     result = result.rstrip('零')

  30.     return result

  31. def tslt_le8(intnum):
  32.     leftint = intnum // 10**4
  33.     rightint = intnum % 10**4

  34.     left = tslt_le4(leftint)
  35.     if left:
  36.         left += '万'

  37.     right = tslt_le4(rightint)
  38.     if leftint and 0 < rightint < 10**3:
  39.         right = '零' + right

  40.     result = left + right

  41.     return result

  42. def tslt_le16(intnum):
  43.     leftint = intnum // 10**8
  44.     rightint = intnum % 10**8

  45.     left = tslt_le8(leftint)
  46.     if left:
  47.         left += '亿'

  48.     right = tslt_le8(rightint)
  49.     if leftint and 0 < rightint < 10**7:
  50.         right = '零' + right

  51.     result = left + right

  52.     if result == '':
  53.         result = '零'

  54.     if result.startswith('一十'):
  55.         result = result[1:]

  56.     return result

  57. for i in (0, 123, 10234, 10034, 1000002, 1000000, 9000000100002300):
  58.     print(i, digit2ChineseDX(i))


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