2008年(47)
分类:
2008-11-12 16:51:03
By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23.
3
7 5
2 4 6
8 5 9 3
That is, 3 + 7 + 4 + 9 = 23.
Find the maximum total from top to bottom of the triangle below:
75
95 64
17 47 82
18 35 87 10
20 04 82 47 65
19 01 23 75 03 34
88 02 77 73 07 63 67
99 65 04 28 06 16 70 92
41 41 26 56 83 40 80 70 33
41 48 72 33 47 32 37 16 94 29
53 71 44 65 25 43 91 52 97 51 14
70 11 33 28 77 73 17 78 39 68 17 57
91 71 52 38 17 14 91 43 58 50 27 29 48
63 66 04 68 89 53 67 30 73 16 69 87 40 31
04 62 98 27 23 09 70 98 73 93 38 53 60 04 23
NOTE: As there are only 16384 routes, it is possible to solve this problem by trying every route. However, , is the same challenge with a triangle containing one-hundred rows; it cannot be solved by brute force, and requires a clever method! ;o)
从(i, j)开始的最大值为(i+1,j)与(i+1,j+1)中的大者加上(i, j)自身,
我们从最下面一行开始计算
def fun18():
fp = open("68.txt", "r")
lines = fp.readlines()
lines.reverse()
line = map(int, lines[0].split())
for i in lines[1:]:
result = map(int, i.split())
for i in range(len(result)):
result[i] += max(line[i], line[i+1])
line = result
return result
answer is 1074
该方法同样可以计算Problem 68
answer is 7273
time:0.0150001049042