Ruby学习之继承

Ruby的继承语法为<

 

例子：

 

#定义基类

class Base
  def meth(info)
   puts "This is Base #{info}"
  end
end

#定义继承类

class Derived < Base
  def meth(info)
   puts "This is derived #{info}"
   super
  end
end

obj1 = Derived.new
obj1.meth("My CU Article")

 

运行的结果如下：

This is derived My CU Article

This is Base My CU Article

其顺序类似C++中析构函数的顺序

 

我们再来看看使用C++来实现

 

class Base
{
public:

/*无论我们是否在此处添加virtual变量，都不能同时调用父类和子类的完全相同的方法meth方法*/
 virtual void meth(char* info)
 {
  cout<<"Base "< }
};

class Derived : public Base
{
public:
 virtual void meth(char* info)
 {
  cout<<"Derived "< }
};

int _tmain(int argc, _TCHAR* argv[])
{
 Base *d = new Derived();
 d->meth("hello");

 return 0;
}