在WinForm中,使C#语言向SQL Server(2005)存储图片并且将图片从数据库中读取出来,显示在窗体中
步骤:
1.首先,在SQL Server中创建一个表,用来存储图片;
示例代码:
use tempdb
go
if exists (select * from sysobjects where name = 'Images')
drop table Images
go
create table Images
(
BLODID int identity not null,
BLOBData image not null
)
2.打开Visual Studio2005,创建一个WinForm应用程序。向Form1中添加一个PictureBox控件,再添加两个
Button控件,将Button1的Text属性分别设为"保存图片","显示图片";
3.在Form1的代码之中,首先引入命名空间:
using System.Data.SqlCilent;
using System.IO;
using System.Drawing.Imaging;
4.编写"保存图片"按钮的单击事件,用于保存图片;
示例代码:
private void button1_Click(object sender, EventArgs e)
{
try
{
string strConn = "Server=.;DataBase=tempdb;Integrated Security=true";
SqlConnection connection = new SqlConnection(strConn);
string sql = "insert into blobtest (blobdata) values (@blobdata)";
SqlCommand command = new SqlCommand(sql, connection);
//图片路径
string picturePath = @"D:\pic.jpg"; //注意,这里需要指定保存图片的绝对路径和图片
//文件的名称,每次必须更换图片的名称,这里很为不便
//创建FileStream对象
FileStream fs = new FileStream(picturePath, FileMode.Open, FileAccess.Read);
//声明Byte数组
Byte[] mybyte = new byte[fs.Length];
//读取数据
fs.Read(mybyte,0,mybyte.Length);
fs.Close();
//转换成二进制数据,并保存到数据库
SqlParameter prm = new SqlParameter
("@blobdata",SqlDbType.VarBinary,mybyte.Length,ParameterDirection.Input,false,0,0,null,DataRowVers
ion.Current,mybyte);
command.Parameters.Add(prm);
//打开数据库连接
connection.Open();
command.ExecuteNonQuery();
connection.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
5.编写"显示图片"的单击事件,将图片从数据库中读取出来显示在PictureBox之中
示例代码:
private void button2_Click(object sender, EventArgs e)
{
try
{
//创建数据库连接字符串
string strConn = "Server=.;DataBase=tempdb;Integrated Security=True";
//创建SqlConnection对象
SqlConnection connection = new SqlConnection(strConn);
//打开数据库连接
connection.Open();
//创建SQL语句
string sql = "select blodid,blobdata from blobtest order by blodid";
//创建SqlCommand对象
SqlCommand command = new SqlCommand(sql,connection);
//创建DataAdapter对象
SqlDataAdapter dataAdapter = new SqlDataAdapter(command);
//创建DataSet对象
DataSet dataSet = new DataSet();