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分类: C/C++

2012-01-18 20:09:04

问题:

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.


答案:25164150

Matlab:
((n+1)*n/2)^2 - n(n+1)(2*n+1)/6
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