Project Euler Problem 1

问题：

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

答案：233168

#include

int main(void)
{
        int sum=0, i=0, k=1000;

        for(i=3; i                sum+=i;

        for(i=5; i        if(i%3!=0)
                sum+=i;
       
        printf("The answer is %d .\n", sum);
        return 0;
}