从ip.txt里读取IP.然后把IP地址赋值到一个数组里.
IP文件如下:
Address: 220.181.26.163
Address: 220.181.26.174
Address: 220.181.26.175
Address: 220.181.26.176
Address: 220.181.19.228
Address: 220.181.19.229
Address: 220.181.26.161
Address: 220.181.26.162
方法一:
for x in ` awk '{print $2}' ip.txt `
{
echo $x
}
方法二:
ARRAY=($(awk '{print $2}' ip.txt))
方法三:
n=0;while read a b;do array[$n]=$b;((n++));done
方法四:
n=1
while ((n<=$(cat ip.txt|wc -l)))
do
ipaddr[$n]=$(cat ip.txt|sed -n "${n}p"|awk '{print $2}')
((n+=1))
done
n=`expr $n - 1`
按行读取文件内容:
while read line
do
echo $line
done
阅读(2437) | 评论(0) | 转发(1) |