9＊9乘法口决pl/sql的多种方法实现(一句sql实现)

select r1 || '*' || r1 || '=' || r1 * r1 A,
decode(r2, '', '', r2 || '*' || r1 || '=' || r2 * r1) b,
decode(r3, '', '', r3 || '*' || r1 || '=' || r3 * r1) C,
decode(r4, '', '', r4 || '*' || r1 || '=' || r4 * r1) D,
decode(r5, '', '', r5 || '*' || r1 || '=' || r5 * r1) E,
decode(r6, '', '', r6 || '*' || r1 || '=' || r6 * r1) F,
decode(r7, '', '', r7 || '*' || r1 || '=' || r7 * r1) G,
decode(r8, '', '', r8 || '*' || r1 || '=' || r8 * r1) H,
decode(r9, '', '', r9 || '*' || r1 || '=' || r9 * r1) I
from (select level r1,
lag(level, 1) over(order by level) r2,
lag(level, 2) over(order by level) r3,
lag(level, 3) over(order by level) r4,
lag(level, 4) over(order by level) r5,
lag(level, 5) over(order by level) r6,
lag(level, 6) over(order by level) r7,
lag(level, 7) over(order by level) r8,
lag(level, 8) over(order by level) r9
from dual