关于多目录下makefile的一种写法

     网上有朋友询问多目录下Makefile的写法，我把自己使用多年的Makefile奉上。

 

其中make.include放在根目录下：

INCL_PATH = \
  -I/${PRJ_HOME/incl/
        -I.
       
LIB_PATH = -L$(PRJ_HOME)/lib

SYS_INCL_PATH =
SYS_LIB_PATH  =
SYS_LIBS = -lm -lnsl -ldl

CCC=g++
CCFLAGS  = -g -w -DLinux -DDEBUG -D_USE_MACRO  -DSQL_SYBASE -D_CSERVER_DEBUG_\
            ${INCL_PATH} ${SYS_INCL_PATH}
CPPFLAGS = ${LIB_PATH} ${SYS_LIB_PATH}
CPPLIBS  = ${LIBS}  ${SYS_LIBS}

AR       = ar
ARFLAGS  = -ruv

INSTALL_PATH= $(CMS_HOME)/lib
INSTALL_BIN_PATH= $(CMS_HOME)/bin
TARGET_PATH= ./

OBJECTS=${SOURCES:%.cpp=%.o}

all: ${CLIB} ${PROGRAM}

${CLIB}: ${OBJECTS}
 @if [ ! -d ${TARGET_PATH} ]; then mkdir -p ${TARGET_PATH}; fi
 $(AR) ${ARFLAGS} $@ $(OBJECTS)

${PROGRAM}: ${OBJECTS}
 @if [ ! -d ${TARGET_PATH} ]; then mkdir -p ${TARGET_PATH}; fi
 $(CCC) -o $@ ${CPPFLAGS} $(OBJECTS) $(CPPLIBS)

.cpp.o:
 $(CCC) $(CCFLAGS) -o $@ -c $<

install:
 @if [ "x${CLIB}" != "x" ]; then mkdir -p ${INSTALL_PATH}; cp $(CLIB) $(INSTALL_PATH); fi
 @if [ "x${PROGRAM}" != "x" ]; then mkdir -p ${INSTALL_BIN_PATH}; cp $(PROGRAM) $(INSTALL_BIN_PATH); fi

clean:
 @rm -rf ${OBJECTS} ${CLIB} ${PROGRAM}
 @rm -rf SunWS_cache
 @rm -rf ir.out
 @rm -rf core.*
 @rm -rf my
 @rm -rf you

 

每个目录下：

############################################################
## makefile of libtest.a
############################################################
.SUFFIXES: .cpp

SOURCES  = test.cpp
 
PROGRAM  = test
CLIB     = 
LIBS     =

PRJ_HOME = $(HOME)/project

include ${PRJ_HOME}/makefile.include