Eclipse中raw type generic type 告警问题

总是提示“Iterator is a raw type. References to generic type Iterator should be parameterized”


解决方法： 添加：  @SuppressWarnings("unchecked")

如：

private void addAttributes(ObjectType object, Builder builder, int Id) throws Exception {
    Iterator itAttributes = object.getAttributes();
    while (itAttributes.hasNext()) {
      AttributeType attr = (AttributeType) itAttributes.next();
      if (!attr.getName().equals("Id")) {
        setAttrValue(attr, object, builder, false);
      } else {
        builder.setAttribute(attr.getName(), "" + Id);
      }
    }
  }


修改为

  @SuppressWarnings("unchecked")
private void addAttributes(ObjectType object, Builder builder, int Id) throws Exception {
    Iterator itAttributes = object.getAttributes();
    while (itAttributes.hasNext()) {
      AttributeType attr = (AttributeType) itAttributes.next();
      if (!attr.getName().equals("Id")) {
        setAttrValue(attr, object, builder, false);
      } else {
        builder.setAttribute(attr.getName(), "" + Id);
      }
    }
  }