8位以内的16进制字符串转换为整数

下面的例子展示了如何将8位以内的16进制字符串转换为整数， 我相信这对于很多人都是很有用的，尤其是对用sdk开发的windows程序员，下面的代码可以原封不动的拷贝使用。虽然代码很简单，但是自己写起来还得费一点小心思，

// eg.: lpszHexString = "600107D0"

DWORD HexString2DWORD(LPCTSTR lpszHexString)
{
    int len = lstrlen(lpszHexString);
    if ( len > 8 )
        return 0;

    DWORD res = 0;
    DWORD tmp = 0;
    for ( int i = 0; i < len; i++ )
    {
        if ( lpszHexString[i] >= '0' && lpszHexString[i] <= '9' )
            tmp = lpszHexString[i] - '0';
        else if ( lpszHexString[i] >= 'a' && lpszHexString[i] <= 'f' )
            tmp = lpszHexString[i] - 'a' + 10;
        else if ( lpszHexString[i] >= 'A' && lpszHexString[i] <= 'F' )
            tmp = lpszHexString[i] - 'A' + 10;
        else
            tmp = 0;

        tmp <<= ((len - i - 1) << 2);

        res |= tmp;
    }

    return res;
}

author: thinker
e-mail: cnhnyugmail.com
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