IBM/AIX下找到占用指定端口的进程并杀死它
零、Windows下的方法
> netstat -ano | find "1521"
TCP 0.0.0.0:1521 0.0.0.0:0 LISTENING 2024
> taskkill /pid 2024
一、相关方法的参考资料(转载)
1:首先根据端口号
# netstat -A | grep 1099
返回
f1000089c27a2358 tcp4 0 0 *.389 *.* LISTEN
2:移除sock
# rmsock f100089c27a2358 tcpcb
The socket 0x702f6800 is being held by proccess 4986 (java).
3:杀死进程
# kill 4986
二、功能脚本(原创)
##功能:找到端口所在进程的pid并选择是否杀死此进程
##参数$1 = 端口
!/bin/ksh
function kpd
{
### 扫描端口所在pcb netstat -A | grep $1| head -n 1 ;
pcb=$(netstat -A | grep $1| head -n 1 | awk 'BEGIN{FS=" "}{print $1}');
### 扫描pcb所在进程id
rmsock "$pcb" tcpcb;
pid=$(rmsock "$pcb" tcpcb | awk 'BEGIN{FS=" "}{print $9}');
### 是否杀死进程?
echo "杀死占用端口:"$1" 的进程:"$pid"?(y/n)";
read choice;
if [ "$choice" == "y" ];then
kill -9 "$pid";
echo "已杀死进程:"$pid" .";
fi
}
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### 示例:杀死占用1099端口的进程
# kpd 1099
f1000e00111533b0 tcp 0 0 *.1099 *.* LISTEN
The socket 0x11153008 is being held by proccess 12189714 (java).
杀死占用端口:1099 的进程:12189714?(y/n)
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