怎么介绍?
分类:
2009-03-02 08:23:07
Solution 1:
p: the prob from x= k to x=k-1 (markov chain is homogeneous)
Look at x=0
p=0.5* 1 + 0.5*p^3
Solve p.
Solution 2:
x_n = x_{n-1} + z_n
x_0 = 0, z_n = +2, -1 with probability 1/2.
Let y_n = t^x_n, select t so that y is a martingale.
The condition for y_n to be martingale is 1/2(t^2 + 1/t) = 1.
Solve this equation to get t = (sqrt(5) -1)/2.
y_0 = 1, y_n goes to 0 or stops at 1/t.
Due to optional stopping time theorem, y_n stops at 1/t with probability p, and
p/t + (1-p) 0 = 1.
So p = t.