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分类: Oracle
2019-03-01 11:53:56
49、(11-1) choose the best answer
Examine the structure of the SHIPMENTS table:
You want to generate a report that displays the PO_ID and the penalty amount to be paid(罚款数额) if the SHIPMENT_DATE is later than one month from the PO_DATE. The penalty is $20 per day.
Evaluate the following two queries:
SQL> SELECT po_id, CASE
WHEN MONTHS_BETWEEN (shipment_date,po_date)>1 THEN
TO_CHAR((shipment_date - po_date)*20) ELSE 'No Penalty' END PENALTY
FROM shipments;
SQL>SELECT po_id, DECODE
(MONTHS_BETWEEN(po_date,shipment_date)>1,
TO_CHAR((shipment_date - po_date) * 20, 'NO Penalty') PENALTY
FROM shipments;
Which statement is true regarding the above commands?
A) Only the second query executes successfully but gives a wrong result.
B) Only the second query executes successfully and gives the correct result.
C) Only the first query executes successfully but gives a wrong result.
D) Both execute successfully and give correct results.
E) Only the first query executes successfully and gives the correct result.
Answer:E
(解析:decode 函数的语法是,decode(条件,值 1,返回值 1,值 2,返回值 2,...值 n,返回值 n,缺省值),
所以不能有>1 的条件判断。原来 051 的题。
该语句可以改写为下面的语句:
SELECT empno,hiredate,
CASE
WHEN MONTHS_BETWEEN (sysdate,hiredate)>1
THEN TO_CHAR((sysdate - hiredate )*20)
ELSE 'No Penalty'
END PENALTY
FROM emp;)