题目:
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
解法:
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/**
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* Definition for singly-linked list.
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* public class ListNode {
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* int val;
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* ListNode next;
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* ListNode(int x) {
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* val = x;
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* next = null;
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* }
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* }
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*/
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public class Solution {
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public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
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ListNode prev = new ListNode(0);
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ListNode head = prev;
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int carry = 0;
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while (l1 != null || l2 != null || carry != 0) {
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ListNode cur = new ListNode(0);
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int sum = ((l2 == null) ? 0 : l2.val) + ((l1 == null) ? 0 : l1.val) + carry;
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cur.val = sum % 10;
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carry = sum / 10;
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prev.next = cur;
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prev = cur;
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l1 = (l1 == null) ? l1 : l1.next;
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l2 = (l2 == null) ? l2 : l2.next;
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}
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return head.next;
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}
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}
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