分类: Python/Ruby
2015-09-09 16:25:07
去空格及特殊符号
s.strip().lstrip().rstrip(',')
#strcpy(sStr1,sStr2) sStr1 = 'strcpy' sStr2 = sStr1 sStr1 = 'strcpy2' print sStr2
#strcat(sStr1,sStr2) sStr1 = 'strcat' sStr2 = 'append' sStr1 += sStr2 print sStr1
#strchr(sStr1,sStr2) # < 0 为未找到 sStr1 = 'strchr' sStr2 = 's' nPos = sStr1.index(sStr2) print nPos
#strcmp(sStr1,sStr2)
sStr1 = 'strchr' sStr2 = 'strch'
print cmp(sStr1,sStr2)
#strspn(sStr1,sStr2)
sStr1 = '12345678' sStr2 = '456'
#sStr1 and chars both in sStr1 and sStr2
print len(sStr1 and sStr2)
#strlen(sStr1) sStr1 = 'strlen' print len(sStr1)
#strlwr(sStr1) sStr1 = 'JCstrlwr' sStr1 = sStr1.upper() #sStr1 = sStr1.lower() print sStr1
#strncat(sStr1,sStr2,n) sStr1 = '12345' sStr2 = 'abcdef' n = 3 sStr1 += sStr2[0:n] print sStr1
#strncmp(sStr1,sStr2,n) sStr1 = '12345' sStr2 = '123bc' n = 3 print cmp(sStr1[0:n],sStr2[0:n])
#strncpy(sStr1,sStr2,n) sStr1 = '' sStr2 = '12345' n = 3 sStr1 = sStr2[0:n] print sStr1
#strnset(sStr1,ch,n) sStr1 = '12345' ch = 'r' n = 3 sStr1 = n * ch + sStr1[3:] print sStr1
#strpbrk(sStr1,sStr2) sStr1 = 'cekjgdklab' sStr2 = 'gka' nPos = -1 for c in sStr1: if c in sStr2: nPos = sStr1.index(c) break print nPos
#strrev(sStr1) sStr1 = 'abcdefg' sStr1 = sStr1[::-1] print sStr1
#strstr(sStr1,sStr2)
sStr1 = 'abcdefg' sStr2 = 'cde'
print sStr1.find(sStr2)
#strtok(sStr1,sStr2) sStr1 = 'ab,cde,fgh,ijk' sStr2 = ',' sStr1 = sStr1[sStr1.find(sStr2) + 1:] print sStr1 #或者 s = 'ab,cde,fgh,ijk' print(s.split(','))
delimiter = ',' mylist = ['Brazil', 'Russia', 'India', 'China'] print delimiter.join(mylist)
def addslashes(s): d = {'"':'\\"', "'":"\\'", "\0":"\\\0", "\\":"\\\\"} return ''.join(d.get(c, c) for c in s) s = "John 'Johny' Doe (a.k.a. \"Super Joe\")\\\0" print s print addslashes(s)
def OnlyCharNum(s,oth=''): s2 = s.lower(); fomart = 'abcdefghijklmnopqrstuvwxyz0123456789' for c in s2: if not c in fomart: s = s.replace(c,''); return s; print(OnlyStr("a000 aa-b"))