不用库函数实现统计长字符串中短字符串的个数 C语言实现

#include


int SubString(char* LongString,char* ShortString);
int main(void)
{
char LS[] = "aabcdbcd";
char SS[] = "bcd";
// int num = SubString(LS,SS);
printf("%d\n",SubString(LS,SS));
return 0;
} 
int SubString(char* LongString,char* ShortString)
{
int num=0;
char* p = ShortString;
// int len =  sizeof(ShortString);//sizeof是运算符，不是函数，所以没有头文件 
do
{
if((*(LongString++)) == (*(ShortString++)))
{
if((*ShortString) == '\0')
{
num++;
ShortString = p;
}
}
else
ShortString = p;
}while((*(LongString))!='\0');

return num;
}