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全部博文(72)
2014年(72)
分类: Oracle
2014-06-19 10:38:33
转载请注明出处:http://blog.csdn.net/guoyjoe/article/details/12657479
正确答案:B
Oracle 11g 新特性:Result Cache ,它是存在SHARED POOL中,作用SQL提高性能,如果结果缓存起来,下次查询直接就返回数据,无须再解析丶执行SQL了。大大提高了性能。但缺点是需要在共享池留一块空间出来。
结果集缓存是Oracle 11g新引入的功能,除了可以在服务器端缓存结果之外,还可以在客户端缓存结果。服务器端的Result Cache Memory由两部分组成。
■SQL Query Result Cache:存储SQL查询的结果集。
■PL/SQL Function Result Cache:用于存储过程PL/SQL函数的结果集。
Oracle通过一个新引入初始化参数来控制该Cache的大小(result_cache_max_size)
sys@OCM> show parameter result NAME TYPE VALUE ------------------------------------ ----------- ------------------------------ client_result_cache_lag big integer 3000 client_result_cache_size big integer 0 result_cache_max_result integer 5 result_cache_max_size big integer 3360K result_cache_mode string MANUAL result_cache_remote_expiration integer 0
如果result_cache_max_size=0则表示禁用该特性。参数result_cache_max_result则控制单个缓存结果可以占总的Server Result Cache大小的百分比。
上面显示的参数中result_cache_mode用于控制Server Result Cache的模式,该参数有3个可选设置。
● result_cache_mode=AUTO:则优化器自动判断是否将查询结果缓存。
●result_cache_mode=MANUAL:则需要通过查询提示来告诉优化器是否缓存结果。
●result_cache_mode=FORCE:则尽可能地缓存查询结果,通过提示:no_result_cache可以拒绝缓存。
Ok,下面我们来测Result Cache的性能。
(1)当前我的result_cache_mode为manual,如上所说result_cache_mode=MANUAL:则需要通过查询提示来告诉优化器是否缓存结果。
sys@OCM> show parameter result NAME TYPE VALUE ------------------------------------ ----------- ------------------------------ client_result_cache_lag big integer 3000 client_result_cache_size big integer 0 result_cache_max_result integer 5 result_cache_max_size big integer 3360K result_cache_mode string MANUAL result_cache_remote_expiration integer 0
(2)在没有缓存结果的况情下的测试
gyj@OCM> set autot traceonly; gyj@OCM> select count(*) from t1; Execution Plan ---------------------------------------------------------- Plan hash value: 3724264953 ------------------------------------------------------------------- | Id | Operation | Name | Rows | Cost (%CPU)| Time | ------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 3 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | | | | 2 | TABLE ACCESS FULL| T1 | 2 | 3 (0)| 00:00:01 | ------------------------------------------------------------------- Statistics ---------------------------------------------------------- 1 recursive calls 0 db block gets 6 consistent gets 0 physical reads 0 redo size 526 bytes sent via SQL*Net to client 520 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed
gyj@OCM> set autot traceonly; gyj@OCM> select count(*) from t1; Execution Plan ---------------------------------------------------------- Plan hash value: 3724264953 ------------------------------------------------------------------- | Id | Operation | Name | Rows | Cost (%CPU)| Time | ------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 3 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | | | | 2 | TABLE ACCESS FULL| T1 | 2 | 3 (0)| 00:00:01 | ------------------------------------------------------------------- Statistics ---------------------------------------------------------- 1 recursive calls 0 db block gets 6 consistent gets 0 physical reads 0 redo size 526 bytes sent via SQL*Net to client 520 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed
不管你执行几次select count(*)from t1;,它的consistent gets值都为6.从下面可以看出逻辑读是6(逻辑读= 当前读db block gets+一致性读consistent gets)
(2)在有缓存结果的况情下的测试
gyj@OCM> select /*+ result_cache */ count(*) from t1; Execution Plan ---------------------------------------------------------- Plan hash value: 3724264953 ------------------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Cost (%CPU)| Time | ------------------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 3 (0)| 00:00:01 | | 1 | RESULT CACHE | 83r168smxh22sgfhqrq2u524uv | | | | | 2 | SORT AGGREGATE | | 1 | | | | 3 | TABLE ACCESS FULL| T1 | 2 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------------------ Result Cache Information (identified by operation id): ------------------------------------------------------ 1 - column-count=1; dependencies=(GYJ.T1); attributes=(single-row); name="select /*+ result_cache */ count(*) from t1" Statistics ---------------------------------------------------------- 1 recursive calls 0 db block gets 6 consistent gets 0 physical reads 0 redo size 526 bytes sent via SQL*Net to client 520 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed
gyj@OCM> select /*+ result_cache */ count(*) from t1; Execution Plan ---------------------------------------------------------- Plan hash value: 3724264953 ------------------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Cost (%CPU)| Time | ------------------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 3 (0)| 00:00:01 | | 1 | RESULT CACHE | 83r168smxh22sgfhqrq2u524uv | | | | | 2 | SORT AGGREGATE | | 1 | | | | 3 | TABLE ACCESS FULL| T1 | 2 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------------------ Result Cache Information (identified by operation id): ------------------------------------------------------ 1 - column-count=1; dependencies=(GYJ.T1); attributes=(single-row); name="select /*+ result_cache */ count(*) from t1" Statistics ---------------------------------------------------------- 0 recursive calls 0 db block gets 0 consistent gets 0 physical reads 0 redo size 526 bytes sent via SQL*Net to client 520 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed
看到了吗,第二次执行consistent gets=0,整个逻辑读为0,说明没有执行SQL。发出SQL语句直接从共享池的Result Cache(结果集缓)存中取数据返回给客户端。
一道OCP的题目就引出了好多东西,这道题原本只是考结果缓存池在哪?实际了我们不但要知道它在共享池shared pool中,更重要的,我们要知道它的作用,Result Cache(结果集缓)是提高SQL的查询性能。哈哈。。OCP题库确实是个好东西啊,读懂每道题,转化为自己的知识,1000多道这样折腾下来,你的理论知识不扎实都不可能了。
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