C++程序   名字搜索与程序标记

一：

下面的程序要求用户输入一个名字，然后程序将在用于保存名字的vector中进行搜索以判断vector中是否包含这一名字。如果包含，则程序输出这一名字的含义。如果vector中不包含这一名字，则程序将告诉用户：没有这个名字。

#include<iostream>
#include<string>
#include<vector>

using namespace std;

int main()
{
    cout << "Welcome to the C++ Name Search Programe.";

    //构造两个用于存放string的vector
    vector<string> names;
    vector<string> origins;

    //将数据存入vector
    names.push_back("Barbara");
    origins.push_back("greek,meaning stranger.");

    names.push_back("Kelly");
    origins.push_back("celtic,meaning warrior or defender.");

    names.push_back("Claire");
    origins.push_back("french,meaning bright and clear");

    //推测使用的变量
    string answer,userName;

    do
    {
        bool bDidNotFindIt = true;

        cout << "\nPlease enter a name,such as Kelly: ";
        getline(cin,userName);

        int index = 0;
        while(index < names.size() && bDidNotFindIt == true)
        {
            if(userName == names.at(index))
            {
                cout << "\n Here is your name: " << names.at(index);
                cout << "\n Origin: " << origins.at(index)<< endl;

                bDidNotFindIt = false;
            }
            else
            {
                ++index;
            }
        }

        if(bDidNotFindIt)
        {
            cout << "\n Sorry. "<< userName << " isn't in voctor. "<< endl;
        }

        cout << "Do anther name? yes/no" << endl;
        getline(cin,answer);
    }while(answer == "yes");
    return 0;
}

输出结果为：

Welcome to the C++ Name Search Programe.
Please enter a name,such as Kelly: Kelly


 Here is your name: Kelly
 Origin: celtic,meaning warrior or defender.
Do anther name? yes/no
yes


Please enter a name,such as Kelly: Barbara


 Here is your name: Barbara
 Origin: greek,meaning stranger.
Do anther name? yes/no
yes


Please enter a name,such as Kelly: aa


 Sorry. aa isn't in voctor.
Do anther name? yes/no
no
请按任意键继续. . .

二：

下面使用指针和引用来重新实现一次上面的程序。定义两个使用参数的函数：FillVectors以及SearchFcrName，还定义了一个AskUserForName函数，该函数输入输出都为string对象。程序有三个文件组成。仔细查看源代码，注意程序是如何在NameFunctions.h中把string和vector库包含进来的。之所以在该函数中包含这两个库，是因为我们要在函数的原型声明中用到string和vector。一定要根据代码文件的需要来进行类库的包含操作，不需要多，但也不能少。

NameFunctions.h：

//NameFunctions.h

#include<string>
#include<vector>
using namespace std;

void FillVectors(vector<string> &names, vector<string> &origins);

string AskUserForName();

bool SearchForName(vector<string> &names, vector<string> &origins, string &userName, string &nameOrigin );

NameFunctions.cpp

//NameFunctions.cpp中含有在NameFunctions.h中声明的函数的定义

#include<iostream>
#include<string>
#include<vector>
using namespace std;

bool SearchForName(vector<string> &names, vector<string> &origins, string &userName, string &nameOrigin )
{
    //在vector中进行查找，如果找到则程序结束
    int index = 0;
        while(index < names.size())
        {
            if(userName == names.at(index))
            {
                //找到后对nameOrigin赋值并返回main
                nameOrigin = origins.at(index);
                return true;

            }
            else
            {
                ++index;
            }

            //如果程序执行到这里则说明没有找到
            return false;
        }
}


void FillVectors(vector<string> &names, vector<string> &origins)
{
    //将名字和含义储存在vector中，这些是main中的vector，我们有对它们进行引用的变量
    names.push_back("Barbara");
    origins.push_back("greek,meaning stranger.");

    names.push_back("Kelly");
    origins.push_back("celtic,meaning warrior or defender.");

    names.push_back("Claire");
    origins.push_back("french,meaning bright and clear");
}

string AskUserForName()
{
    string uName;
    cout << "\nPlease enter a name,such as Kelly: ";
    getline(cin,uName);
    return uName;
}

main.cpp：

//程序提示用户输入一个名字，在vector中查找这个名字，如果有，则输出该名字的含义

#include<iostream>
#include<string>
#include<vector>
using namespace std;

#include "NameFunctions.h"

int main()
{
    cout <<"\n Welcome to the C++ Name Search Programe.";
     //构造两个用于存放string的vector
    vector<string> names;
    vector<string> origins;

    //调用函数来对着两个vector进行赋值
    FillVectors(names,origins);

    //声明用来储存名字和结果的变量
    string userName, nameOrigin, answer;
    bool bFoundIt;

    do
    {
        userName = AskUserForName();

        //bFoundIt指示名字找到
        bFoundIt = SearchForName(names,origins,userName,nameOrigin);
        if(bFoundIt)
        {
            cout << "\n Here is your name: " << userName;
            cout << "\n origin: " << nameOrigin << endl;
        }
        else
        {
             cout << "\n Sorry. "<< userName << " isn't in voctor. "<< endl;
        }

        cout << "Do anther name? yes/no ";
        getline(cin,answer);

    }while(answer == "yes");

    return 0;
}

输出结果为：

Welcome to the C++ Name Search Programe.
Please enter a name,such as Kelly: Kelly

 Sorry. Kelly isn't in voctor.
Do anther name? yes/no yes

Please enter a name,such as Kelly: aaa

 Sorry. aaa isn't in voctor.
Do anther name? yes/no no
请按任意键继续. . .