C程序设计语言学习--导言（8）

将文本中的table转换成空格。
如果table后的字符数肯定是4的倍数。（默认一个table为4个空格）
首先得统计字符数，然后判断和4的倍数之间的差值，然后输出这么多空格~~

#include

#define TABSIZE 4

int main(void)
{
    int c,pos = 0,nb;


    while((c = getchar()) != EOF){
        if(c == '\t'){
            nb = TABSIZE - (pos - 1)/TABSIZE;

            while(nb > 0){
                putchar(' ');
                nb --;
            }
        }else if(c == '\n'){
            putchar('c');
            pos = 1;
        }else{
            pos ++;
            putchar(c);
        }
    }
    return 0;
}

将连续的空格转换成最多的TABLE和空格符。

#include

#define TABSIZE 4

int main(void)
{
    int c,nb,nt,pos;
    int i;
    nb = nt = pos = 0;

    while((c = getchar()) != EOF){
        pos ++;
        if(c == ' '){
            if(pos % TABSIZE != 0){
                nb++;
            }else{
                nb = 0;
                nt ++;
            }
        }else{
            for(;nt > 0 ;nt --){
                putchar('\t');
            }

            if(c == '\t'){
                nb = 0;
            }else{
                for(;nb > 0;nb --){
                    putchar(' ');
                }
            }
            putchar(c);

            if(c == '\n'){
                pos = 0;
             }else if (c == '\t'){
                pos = pos + (TABSIZE - (pos- 1) % TABSIZE) -1;
            }
        }
    }
    return 0;
}