几个批量修改目录文件名的脚本文件

最近在测试环境维护时，找看到几个批量修改目录和文件名以及文件内容的脚本文件，贴出来分享下

 

一 修改目录 rename_dir.sh

#!/bin/sh
#

if [ $# != 3 ]; then
echo "missing operand"
echo "Usage: rename.sh srcstr deststr path"
echo "Sample: rename.sh from to ."
exit 0
fi

str1="$1"
str2="$2"
path="$3"

for f in $(find "$path" -type d)
do
fn=`echo ${f} | grep ${str1}`
if [ $? == 0 ]; then
fn=`echo ${f} | sed -e "s/${str1}/${str2}/g"`
mv ${f} ${fn}
echo "${f} --->>> ${fn}"
fi
done

echo "all done!"

二 修改文件名 rename_file.sh

#!/bin/sh
#

if [ $# != 4 ]; then
echo "missing operand"
echo "Usage: rename.sh srcstr deststr path file"
echo "Sample: rename.sh from to . *.sh"
exit 0
fi

str1="$1"
str2="$2"
path="$3"
file="$4"

for f in $(find "$path" -name "$file" -type f)
do
fn=`echo ${f} | grep ${str1}`
if [ $? == 0 ]; then
fn=`echo ${f} | sed -e "s/${str1}/${str2}/g"`
mv ${f} ${fn}
echo "${f} --->>> ${fn}"
fi
done

echo "all done!"

 

三 修改文件中的字符串 replace_in_file.sh

 

#!/bin/sh
#

if [ $# != 4 ]; then
echo "missing operand"
echo "Usage: replace_in_file.sh srcstr deststr path file"
echo "Sample: replace_in_file.sh 192.168.0.1 xxx.xxx.xxx.xxx . *.sh"
exit 0
fi

str1="$1"
str2="$2"
path="$3"
file="$4"

for f in $(find "$path" -name "$file" -type f | xargs grep -l "$str1")
do
fn="${f}.$(date +%s)"
cp -f "$f" "$fn"
sed -e "s/$str1/$str2/g" $fn > $f
rm -rf $fn
echo "${f} replaced"
done

echo "all done!"