operator<< overloading with template

#include <iostream>
using namespace std;
template <class T>
class Vector
{
    T *m_t;
    int dim;
public:
      Vector(int n,T t[]){
           dim = n;
           m_t = new T[dim];
           for (int i=0;i<dim;i++)
                m_t[i] = t[i];
        }
        ~Vector(){
          delete[] m_t;
      }
      Vector operator+(const Vector &)const;
      Vector &operator=(const Vector &);
      friend ostream &operator<<(ostream &out,const Vector<T> &v){
            out << '(';
            for (int i=0;i< v.dim-1;i++)
              out << v.m_t[i] << ',';
            return out <<  v.m_t[v.dim-1]<< ')';
      }
};
template <class T>
Vector<T> Vector<T>::operator+( const Vector<T> &v)const{
       T *t;
       t = new T[dim];
       for (int i=0;i<dim;i++){
            t[i] = m_t[i] + v.m_t[i];
       }
       return Vector<T>(dim,t);
}

template <class T>
Vector<T> &Vector<T>::operator=( const Vector<T> &v){
for (int i=0;i<dim;i++)
        m_t[i] = v.m_t[i];
       return *this;
}
int main(){
     int  t[3];
     int i;
     for (i = 0;i < 3; i++)
          t[i] = i;
     Vector<int> v1(3, t);
            for (i = 0;i < 3; i++)
          t[i] = i+5;
     Vector<int> v2(3,t),v(3,t);
            v = v1+v2;
     cout << v <<endl;
}

As show in the code, operator<< has to be declared friend and inline function!