YYYYDDD2YYYYMMDD(日期格式转换)

#include<iostream>

using namespace std;



int main()

{

    int mb[12] = {0,  31,  59,  90, 120, 151, 181, 212, 243, 273, 304, 334};

    int input,year,month,day;

    cout<<"input the yyyyddd format of date:"<<endl;

    cin>>input;

    year=input/1000;

    if((year%4==0)&&((year%100!=0)||(year%400==0)))

    //mb[12] = {0,  31,  60,  91, 121, 152, 182, 213, 244, 274, 305, 335};

   {

    cout<<"leap year"<<endl;

    for(int i=2;i<12;i++)

    mb[i]+=1;

    }

    input-=year*1000;



    cout<<"year:"<<year<<endl;

    for(int i=0;i<12;i++)

    {

            if(mb[i]>=input)

            {

                   month=i;

                   break;

            }

    }

     cout<<"month:"<<month<<endl;

    day=input-mb[month-1];

    cout<<"day:"<<day<<endl;

    return 0;

}