指针的转换Zz

#include <iostream>

#include <string.h>



using namespace std;



int main()

{

char val[10] = {0x01, 0x23, 0x6a, 0x85, 0x03,

       0x32, 0x26, 0x2f, 0x98, 0x25};

int a;

a = *((long int *)val + 1);

cout << hex << a << endl;



unsigned long long int b;

b = *(unsigned long long int *)(val);

 cout << hex << b << endl;

    char ch[6];

    memcpy(ch, val + 4, 6);

    cout << hex  << (int)ch[0] << endl;


    /*注意：memcpy（）最后一个参数指的是多少个bytes。若想把val[1] ~ val[8]保存

     * 为两个int值，则需要写成 memcpy(c, (long int *)(val + 1), 8)

     * 该函数的意思是将(long int *)(val + 1)后面的8个bytes复制到指针c的位置。

     * */

    int c[2];

    memcpy(c, (long int *)(val + 1), 8);

    cout << hex << *((long int *)(val + 1)) << endl;

    cout << hex << c[0] << endl;

    cout << hex << c[1] << endl;


return 0;

}

output：

2f263203

2f263203856a2301

3

3856a23

3856a23

982f2632