Chinaunix首页 | 论坛 | 博客
  • 博客访问: 473167
  • 博文数量: 120
  • 博客积分: 1853
  • 博客等级: 上尉
  • 技术积分: 1177
  • 用 户 组: 普通用户
  • 注册时间: 2011-10-22 22:40
文章分类

全部博文(120)

文章存档

2013年(16)

2012年(104)

分类: Python/Ruby

2012-02-25 15:18:47


1. 读入一个文件夹,察看其下所有文件的属性
read -p "enter the dir:" dir
filelist=`ls $dir`                   #`` 而非‘’
for filename  in $filelist
do
        perm=""           # 每次都重置为空
        test -r "$dir/$filename" && perm="$perm readable"
        test -w "$dir/$filename" && perm="$perm writable"
        test -x "$dir/$filename" && perm="$prem excuted"
        echo "$dir/$filename   has the permssions of $perm"
done

2. 输入的如果是yes就继续,如果是no,就停止
read -p "input y/n: " yn
if [ "$yn" == "Y" -o "$yn" == "y" ]; then   #此处的-o用法 和“$y”而不能是$y,且if之后有,
        echo "ok,continue"
        elif [ "yn" == "N" -o "$yn" == "n" ];then  
        echo "oh,interrupt"
        else
                echo "i don't know what your choice"
fi


3.通过端口检测使用的协议
#detect the www ,ftp ssh
echo "the www ,ftp ,ssh will be detect"
testing=`netstat -tunl|cut -d ":" -f 1|cut -d " " -f 1` #此处的netstat -tnul 还有后面的cut的格式
if [ "$testing" == "80" ];then
        echo "www is running on your sysytem"
        elif [ "$tesing" == "21" ];then
        echo "ftp is ruuning on your sysytem"
        elif [ "$tesing" == "22" ];then
        echo "ssh is running on your system"
        else
                echo "none of the www ftp ssh is running on your system"
                fi
4.看看/etc/passwd里面的用户在第几行
#output the users of passwd
accountlist=`cat /etc/passwd|cut -d ":" -f 1`
line=1
for account in $accountlist
do
    echo "the $line  is $account"
    line=$(($line + 1))
done

5. 写一个文件,文件名是你输入的名字加日期
echo -e "i will use touch make a file "
read -p  "please input a fileuser" fileuser
filename=${fileuser:-"filename"}
date1=`date --date='2 days ago' +%F`
date2=`date --date='1 days ago' +%F`
date3=`date +%Y%m%d`
file1="$filename""$date1"
file2="$filename""$date2"
file3="$filename""$date3"
touch $file1
touch $file2
touch $file3

6.数值的加法 
echo -e "you can input two numbers,i will compute them"
read -p "the first  number" num1
read -p "the second  number" num2
total=$(($num1+$num2))                                      #here the + could be replaced by */ %*
echo "the total number of $num1 and $num2 is $total "
 
7.查看文件的存在性,是否是目录及文件的权限
#!bin/bash
#program 
#     let user input a filename ,the program will searchfilename
#   1.exit ? 2.file/directory ? 3 file permissions
#history
#2/24/2012        Vbird  first release
PATH=/usr/lib/lightdm/lightdm:/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games
export PATH


#1.input a filename
read -p "please input a filename:  " filename
test ! -e  $filename && echo "filename doesn't exit" && exit 0
#2.test the filetype
test -f  $filename && filetype="regular file"
test -d  $filename && filetype="directory file"
#3.test the permissions
test -r  $filenam &&  perm="readable" 
test -w  $filenam &&  perm="$perm writable"
test -x  $filenam &&  perm="$perm excutalbe"
#4.output the result
echo "the $filename is a $filetype "
echo "the $filename has the $perm of permissions"
8.test yes or no 和上面的一个比价类似
#test yes or no

read -p "input yes or no: " yn
[ "$yn" == "Y" -o "$yn" == "y" ]&& echo "ok,continue"&&exit 0
[ "$yn" == "N" -o "$yn" == "n" ]&& echo "oh,interrupt"&&exit 0
echo "i don't know what your choice"
阅读(4426) | 评论(0) | 转发(0) |
给主人留下些什么吧!~~