Linux小技巧集锦

需求： A文件是一个文件列表，B文件每一行包含了A文件某行，要从B中抽取出包含了A中的行

awk '{print $0}' A.txt | xargs -i grep {} B.txt > outFile

用一个shell脚本实现也是可以的，脚本如下：

#!/bin/sh

if [ $# -ne 3 ];then
    echo "parameter error"
    echo "usage:`basename $0` regFile targetFile outFile"
    exit 1
fi

regFile=$1
targetFile=$2
outFile=$3

if [ ! -f $regFile -o ! -f $targetFile ];then
    echo "$regFile or $targetFile doesn't exist,please check it"
    exit 1
fi

if [ -f $outFile ];then
    rm $outFile
fi

while read curLine
do
    grep $curLine $targetFile >> $outFile
done < $regFile

echo "parse lines from $targetFile with $regFile to $outFile"
echo "==============\nfinished"