dyli指针初探

#include <stdio.h>

int main(int argc,char ** argv)
{
        char *p;
        printf("************************************\n");
        printf("p=%d,it is an address\n",p);
        p='\0';
        printf("p='\'0,print p= %c\n",p);
        p='0';
        printf("p='0',print %c! \n\n\n",p);


        char *p1;
        printf("************************************\n");
        p1="adcdefg";
        printf("p1 can print them '%s'\n\n\n",p1);


        char *p3;
        printf("************************************\n");
        p3=&("abcdefg"[5]);
        printf("p3=&(''abcdefg''[5]) print: %s\n",p3);
        char str[] = "adcedfg";
        p3=&str[5];
        printf("'p3=&str[5]' will print %s too \n",p3);



        char *p4;
        printf("************************************\n");
        *p4="abcdefg"[5];
        printf("print p4= %s\n",*p4);

        char *p5;
        p5=&("abcdefg"[5]);
        printf("%s\n",p5);

        return 0;
}

运行效果：

************************************
p=1307813,it is an address
p=''0,print p=
p='0',print 0!


************************************
p1 can print them 'adcdefg'


************************************
p3=&(''abcdefg''[5]) print: fg
'p3=&str[5]' will print fg too
************************************
段错误