判断任意给定的数 是否是 回文数

#include<stdio.h>
int Ispalindrome(int num)
{
        int origion = num;
        int pal = 0;
        while(num){
                pal *= 10;
                pal += num%10;
                num /= 10;
                 }
        return origion == pal;
}
int main()
{
        int a = 125321;
        printf("%s\n",Ispalindrome(a)?"yes!":"No!");
}