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杭州智链达数据有限公司技术总监,兼联合创始人

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分类: LINUX

2011-12-22 14:41:13

04年时维护的第一个商业服务就用了两次fork产生守护进程的做法,前两天在网上看到许多帖子以及一些unix书籍,认为一次fork后产生守护进程足够了,各有道理吧,不过多了一次fork到底是出于什么目的呢?


进程也就是task,看看内核里维护进程的数据结构task_struct,这里有两个成员:

struct task_struct 
volatile long state; /* -1 unrunnable, 0 runnable, >0 stopped */ 
... }
看看include/linux/sched.h里的value取值:

#define TASK_RUNNING 0
#define TASK_INTERRUPTIBLE 1
#define TASK_UNINTERRUPTIBLE 2
#define TASK_STOPPED 4
#define TASK_TRACED 8
#define EXIT_ZOMBIE 16
#define EXIT_DEAD 32
可以看到,进程状态里除了大家都理解的running/interuptible/uninterruptible/stop等状态外,还有一个ZOMBIE状态,这个状态是怎么回事呢?


这是因为linux里的进程都属于一颗树,树的根结点是linux系统初始化结束阶段时启动的init进程,这个进程的pid是1,所有的其他进程都是它的子孙。除了init,任何进程一定有他的父进程,而父进程会负责分配(fork)、回收(wait4)它申请的进程资源。这个树状关系也比较健壮,当某个进程还在运行时,它的父进程却退出了,这个进程却没有成为孤儿进程,因为linux有一个机制,init进程会接管它,成为它的父进程。这也是守护进程的由来了,因为守护进程的其中一个要求就是希望init成为守护进程的父进程。


如果某个进程自身终止了,在调用exit清理完相关的内容文件等资源后,它就会进入ZOMBIE状态,它的父进程会调用wait4来回收这个task_struct,但是,如果父进程一直没有调用wait4去释放子进程的task_struct,问题就来了,这个task_struct谁来回收呢?永远没有人,除非父进程终止后,被init进程接管这个ZOMBIE进程,然后调用wait4来回收进程描述符。如果父进程一直在运行着,这个ZOMBIE会永远的占用系统资源,用KILL发任何信号量也不能释放它。这是很可怕的,因为服务器上可能会出现无数ZOMBIE进程导致机器挂掉。


来看看内核代码吧。进程在退出时执行sys_exit(C程序里在main函数返回会执行到),而它会调用do_exit,do_exit首先清理进程使用的资源,然后调用exit_notify方法,将进程置为僵尸ZOMBIE状态,决定是否要以init进程做为当前进程的父进程,最后通知当前进程的父进程:

kernel/exit.c

static void exit_notify(struct task_struct *tsk)
{
int state;
struct task_struct *t;
struct list_head ptrace_dead, *_p, *_n;

if (signal_pending(tsk) && !tsk->signal->group_exit
   && !thread_group_empty(tsk)) {
/*
* This occurs when there was a race between our exit
* syscall and a group signal choosing us as the one to
* wake up.  It could be that we are the only thread
* alerted to check for pending signals, but another thread
* should be woken now to take the signal since we will not.
* Now we'll wake all the threads in the group just to make
* sure someone gets all the pending signals.
*/
read_lock(&tasklist_lock);
spin_lock_irq(&tsk->sighand->siglock);
for (t = next_thread(tsk); t != tsk; t = next_thread(t))
if (!signal_pending(t) && !(t->flags & PF_EXITING)) {
recalc_sigpending_tsk(t);
if (signal_pending(t))
signal_wake_up(t, 0);
}
spin_unlock_irq(&tsk->sighand->siglock);
read_unlock(&tasklist_lock);
}

write_lock_irq(&tasklist_lock);

/*
* This does two things:
*
  * A.  Make init inherit all the child processes
* B.  Check to see if any process groups have become orphaned
* as a result of our exiting, and if they have any stopped
* jobs, send them a SIGHUP and then a SIGCONT.  (POSIX 3.2.2.2)
*/

INIT_LIST_HEAD(&ptrace_dead);
forget_original_parent(tsk, &ptrace_dead);
BUG_ON(!list_empty(&tsk->children));
BUG_ON(!list_empty(&tsk->ptrace_children));

/*
* Check to see if any process groups have become orphaned
* as a result of our exiting, and if they have any stopped
* jobs, send them a SIGHUP and then a SIGCONT.  (POSIX 3.2.2.2)
*
* Case i: Our father is in a different pgrp than we are
* and we were the only connection outside, so our pgrp
* is about to become orphaned.
*/
 
t = tsk->real_parent;
if ((process_group(t) != process_group(tsk)) &&
   (t->signal->session == tsk->signal->session) &&
   will_become_orphaned_pgrp(process_group(tsk), tsk) &&
   has_stopped_jobs(process_group(tsk))) {
__kill_pg_info(SIGHUP, (void *)1, process_group(tsk));
__kill_pg_info(SIGCONT, (void *)1, process_group(tsk));
}

/* Let father know we died 
*
* Thread signals are configurable, but you aren't going to use
* that to send signals to arbitary processes. 
* That stops right now.
*
* If the parent exec id doesn't match the exec id we saved
* when we started then we know the parent has changed security
* domain.
*
* If our self_exec id doesn't match our parent_exec_id then
* we have changed execution domain as these two values started
* the same after a fork.
*
*/
if (tsk->exit_signal != SIGCHLD && tsk->exit_signal != -1 &&
   ( tsk->parent_exec_id != t->self_exec_id  ||
     tsk->self_exec_id != tsk->parent_exec_id)
   && !capable(CAP_KILL))
tsk->exit_signal = SIGCHLD;


/* If something other than our normal parent is ptracing us, then
* send it a SIGCHLD instead of honoring exit_signal.  exit_signal
* only has special meaning to our real parent.
*/
if (tsk->exit_signal != -1 && thread_group_empty(tsk)) {
int signal = tsk->parent == tsk->real_parent ? tsk->exit_signal : SIGCHLD;
do_notify_parent(tsk, signal);
} else if (tsk->ptrace) {
do_notify_parent(tsk, SIGCHLD);
}

state = EXIT_ZOMBIE;
if (tsk->exit_signal == -1 && tsk->ptrace == 0)
state = EXIT_DEAD;
tsk->exit_state = state;

/*
* Clear these here so that update_process_times() won't try to deliver
* itimer, profile or rlimit signals to this task while it is in late exit.
*/
tsk->it_virt_value = 0;
tsk->it_prof_value = 0;

write_unlock_irq(&tasklist_lock);

list_for_each_safe(_p, _n, &ptrace_dead) {
list_del_init(_p);
t = list_entry(_p,struct task_struct,ptrace_list);
release_task(t);
}

/* If the process is dead, release it - nobody will wait for it */
if (state == EXIT_DEAD)
release_task(tsk);

/* PF_DEAD causes final put_task_struct after we schedule. */
preempt_disable();
tsk->flags |= PF_DEAD;
}

大家可以看到这段内核代码的注释非常全。forget_original_parent这个函数还会把该进程的所有子孙进程重设父进程,交给init进程接管。


回过头来,看看为什么守护进程要fork两次。这里有一个假定,父进程生成守护进程后,还有自己的事要做,它的人生意义并不只是为了生成守护进程。这样,如果父进程fork一次创建了一个守护进程,然后继续做其它事时阻塞了,这时守护进程一直在运行,父进程却没有正常退出。如果守护进程因为正常或非正常原因退出了,就会变成ZOMBIE进程。

如果fork两次呢?父进程先fork出一个儿子进程,儿子进程再fork出孙子进程做为守护进程,然后儿子进程立刻退出,守护进程被init进程接管,这样无论父进程做什么事,无论怎么被阻塞,都与守护进程无关了。所以,fork两次的守护进程很安全,避免了僵尸进程出现的可能性。

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