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# retrieve the file information from a selected folder
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# sort the files by last modified date/time and display in order newest file first
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# tested with Python24 vegaseat 21jan2006
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import os, glob, time
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# use a folder you have ...
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root = 'D:\\Zz1\\Cartoons\\' # one specific folder
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#root = 'D:\\Zz1\\*' # all the subfolders too
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print '-'*60 # just vanity
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date_file_list = []
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for folder in glob.glob(root):
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print "folder =", folder
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# select the type of file, for instance *.jpg or all files *.*
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for file in glob.glob(folder + '/*.*'):
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# retrieves the stats for the current file as a tuple
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# (mode, ino, dev, nlink, uid, gid, size, atime, mtime, ctime)
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# the tuple element mtime at index 8 is the last-modified-date
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stats = os.stat(file)
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# create tuple (year yyyy, month(1-12), day(1-31), hour(0-23), minute(0-59), second(0-59),
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# weekday(0-6, 0 is monday), Julian day(1-366), daylight flag(-1,0 or 1)) from seconds since epoch
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# note: this tuple can be sorted properly by date and time
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lastmod_date = time.localtime(stats[8])
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#print image_file, lastmod_date # test
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# create list of tuples ready for sorting by date
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date_file_tuple = lastmod_date, file
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date_file_list.append(date_file_tuple)
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#print date_file_list # test
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date_file_list.sort()
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date_file_list.reverse() # newest mod date now first
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print "%-40s %s" % ("filename:", "last modified:")
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for file in date_file_list:
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# extract just the filename
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folder, file_name = os.path.split(file[1])
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# convert date tuple to MM/DD/YYYY HH:MM:SS format
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file_date = time.strftime("%m/%d/%y %H:%M:%S", file[0])
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print "%-40s %s" % (file_name, file_date)
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