import urllib2
import re
url_new = ''
url_pattern = ''
for i in range(400):
text =urllib2.urlopen(url_new).read()
text = text.split("and the next nothing is ", 1)[-1]
url_new = url_pattern+text
print i,url_new
|
还是觉得自己很山寨,首先400个url跑过之后,根据提示从46059开始,跑过10个左右后,碰到peak.html
替换linkedlist,就过关了。
阅读(518) | 评论(0) | 转发(0) |