Gurad的 A + B代码

//Gurad的代码
#include<stdio.h>
#include<string.h>

char *num[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
int numTran(char a[])
{
    for(int i = 0; i < 10; i++)
        if(!strcmp(a, num[i]))
            return i;
    return 0;
}

int main()
{
    char equl[50];
    char numa[10];
    char numb[10];
    char numc[10];
    char numd[10];
    while(1)
    {
        gets(equl);
        memset(numa, 0, 10);
        memset(numb, 0, 10);
        memset(numc, 0, 10);
        memset(numd, 0, 10);
        int i, j, k;
        int isDoubleA, isDoubleB;
        isDoubleA = isDoubleB = 0;
        for(i = 0; equl[i] != '+'; i++)
            ;
        for(j = 0; equl[j] != ' '; j++)
            numa[j] = equl[j];//a
        numa[j] = '\0';

        for(k = j + 1; k < i - 1; k++)
        {
            isDoubleA = 1;
            numb[k - j - 1] = equl[k];
        }
        numb[k - j - 1] = '\0';//b

        for(;  equl[i] != '='; i++)
            ;

        if(isDoubleA)
            k += 3;
        else
            k += 2;

        for( j = k; equl[j] != ' '; j++)
            numc[j - k] = equl[j];//c
        numc[j - k] = '\0';

        for(k = j + 1; k < i - 1; k++)
        {
            isDoubleB =1;
            numd[k - j - 1] = equl[k];//d
        }
        numd[k - j - 1] = '\0';

        int a = numTran(numa);
        if(isDoubleA)
        {

            a = a*10 + numTran(numb);
            //printf("%d\n", numTran(numb));
        }

        int b = numTran(numc);
        if(isDoubleB)
        {
            b = b*10 + numTran(numd);
            //printf("%d\n", numTran(numd));
        }
        if(a == 0 && b == 0)
            break;

        printf("%d\n", a + b);
    }
    return 0;
}