PHP根据URL判断是否弹出窗口

$referer = $_SERVER['HTTP_REFERER'];
if(!$referer == "){
                if(ereg('http',$referer)){
                                $referer = @explode('.',$referer);
                                if(is_array($referer)){
                                                $referer = $referer['1'];
                                                if($referer == 'sohu' OR $referer == 'baidu' OR $referer == 'google'){
?>

                                                }
                                }
                }
}
?>
 

 

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