python解析window快捷方式

python 解析.lnk文件,获取源文件地址的简单方法

import struct

target = ''

try:
    with open(path, 'rb') as stream:
        content = stream.read()

        # skip first 20 bytes (HeaderSize and LinkCLSID)
        # read the LinkFlags structure (4 bytes)
        lflags = struct.unpack('I', content[0x14:0x18])[0]
        position = 0x18

        # if the HasLinkTargetIDList bit is set then skip the stored IDList
        # structure and header
        if (lflags & 0x01) == 1:
            position = struct.unpack('H', content[0x4C:0x4E])[0] + 0x4E

        last_pos = position
        position += 0x04

        # get how long the file information is (LinkInfoSize)
        length = struct.unpack('I', content[last_pos:position])[0]

        # skip 12 bytes (LinkInfoHeaderSize, LinkInfoFlags, and VolumeIDOffset)
        position += 0x0C

        # go to the LocalBasePath position
        lbpos = struct.unpack('I', content[position:position+0x04])[0]
        position = last_pos + lbpos

        # read the string at the given position of the determined length
        size= (length + last_pos) - position - 0x02
        temp = struct.unpack('c' * size, content[position:position+size])
        target = ''.join([chr(ord(a)) for a in temp])
except:
    # could not read the file
    pass

return target

可以正确获取Program Files下的文件路径

获取desktop下文件的时候会拆分为 用户目录   空格   相对目录

其他诸如或去扫雷.lnk估计也不行,但是大致可用了

顺别贴一个lnk文件结构
https://ithreats.files.wordpress.com/2009/05/lnk_the_windows_shortcut_file_format.pdf

看了下好像不太对得上, 不知道是不是我数错了偏移量,反正也懒得纠结了