分类：
2010-11-07 00:42:27
现举个简单的例子来Linux多线程编程，熟悉互斥锁和条件变量对共享资源的保护。首先，建立两个线程，然后线程1用来输出非3的倍数的值，线程2用来输出3的倍数的值。
#include
#include
#include
#include
pthread_mutex_t mutex;
pthread_cond_t cond;
int i=0;
void *thread1()
{
while (i < 9)
{
pthread_mutex_lock(&mutex);
i++;
/*如果条件满足，唤醒线程2*/
if (i%3 == 0)
pthread_cond_signal(&cond);
else
printf("thread1:%d\n", i);
pthread_mutex_unlock(&mutex);
sleep(1);
}
return NULL;
}
void *thread2()
{
while(i < 9)
{
pthread_mutex_lock(&mutex);
/*如果条件不满足，线程自己挂起并且解锁*/
while (i%3 != 0)
pthread_cond_wait(&cond, &mutex);
/*本线程被唤醒后，在此接着执行*/
printf("thread2:%d\n", i);
pthread_mutex_unlock(&mutex);
sleep(1);
}
return NULL;
}
int main()
{
pthread_t t_1;
pthread_t t_2;
pthread_mutex_init(&mutex, NULL);
pthread_cond_init(&cond, NULL);
int ret;
ret = pthread_create(&t_1, NULL, thread1, NULL);
if(ret != 0)
printf ("Create pthread1 error!\n");
ret = pthread_create(&t_2, NULL, thread2, NULL);
if(ret != 0)
printf ("Create pthread2 error!\n");
pthread_join(t_1, NULL);
pthread_join(t_2, NULL);
pthread_mutex_destroy(&mutex);
pthread_cond_destroy(&cond);
return 0;
}
# gcc –Wall –g –lpthread thread.c –o thread.exe
# ./thread.exe
运行结果：
thread1:1
thread1:2
thread2:3
thread1:4
thread1:5
thread2:6
thread1:7
thread1:8
thread2:9
