Python查询手机号码归属

看到手机能够显示手机号码归属觉得挺实用的，在网上搜索下发现也有现成的数据库，用Python实现了下。

 

 

Python 2.6.2 (r262:71600, Aug 4 2009, 09:26:47)
[GCC 3.4.6 20060404 (Red Hat 3.4.6-10)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> from PhoneRegion import getRegion,loadRegion
>>> numsdb = loadRegion()
>>> print getRegion('1234123',numsdb)
未知,未知
>>> print getRegion('15213492123',numsdb)
未知,未知
>>> print getRegion('13213492123',numsdb)
河南濮阳,联通130卡
>>> print getRegion('13513492123',numsdb)
河北沧州,移动全球通卡

 

#!/usr/bin/env python
# -*- coding=utf-8 -*-

import re
import sys
import gzip
numberRe = re.compile('^1[0-9]{10}$')
numsDbRe = re.compile('(^1[0-9]{6}) (.*) (.*)')

def getRegion(number,numsDb):
    if not numberRe.search(number):
        return '未知,未知'
    if not numsDb:
        return '未知,未知'

    k = number[0:3]
    v = number[3:7]
    if not k in numsDb:
        return '未知,未知'
    else:
        region = numsDb[k].get(v,('未知','未知'))
        return ','.join(region)

def loadRegion():
    RegionDb = {}
    try:
        for line in gzip.open('numsdb.tar.gz').readlines():
            line = line.strip()
            m = numsDbRe.search(line)
            if m:
                nums,area,card = m.groups()
                k = nums[0:3]
                v = nums[3:7]
                if k in RegionDb:
                    RegionDb[k][v] = (area,card)
                else:
                    RegionDb[k]={}
                    RegionDb[k][v] = (area,card)
        return RegionDb
    except Exception,e:
        print e
        return {}

if __name__ == '__main__':
    numsDb = loadRegion()
    try:
        number = sys.argv[1]
        print number,getRegion(number,numsDb)
    except:
        pass

 

文件:	numsdb.tar.gz
大小:	341KB
下载:	下载