Oracle存储过程中去掉重复字符串函数

     来源：赛迪网技术社区    作者：shangyang

以下函数是本人在编写Oracle数据库存储过程时写的函数,觉得该函数通用性较强,因此发表出来供需要的人参考。

这个函数的功能主要是用于去除给定字符串中重复的字符串.在使用中需要指定字符串的分隔符.示例:

str := MyReplace('13,14,13,444', ',');

输出:

13,14,444

create or replace function MyReplace(oldStr varchar2, sign varchar2) return varchar2 is
  str varchar2(1000);
  currentIndex number; 
  startIndex number;
  endIndex number;

  type str_type is table of varchar2(30)
       index by binary_integer;
  arr str_type;

  Result varchar2(1000);
begin     
  if oldStr is null then
    return ('');
  end if;
  
  str := oldStr;
  
  currentIndex := 0;
  startIndex := 0;
  loop
    currentIndex := currentIndex + 1;
    endIndex := instr(str, sign, 1, currentIndex);
    if (endIndex <= 0) then
      exit;
  end if;
    
  arr(currentIndex) := trim(substr(str, startIndex + 1, endIndex - startIndex - 1));
  startIndex := endIndex;
  end loop;

取最后一个字符串:

arr(currentIndex) := substr(str, startIndex + 1, length(str));

去掉重复出现的字符串:

for i in 1.. currentIndex - 1 loop
  for j in i + 1..currentIndex loop
    if arr(i) = arr(j) then
      arr(j) := '';
    end if;
  end loop;
  end loop;

  str := '';
  for i in 1..currentIndex loop
  if arr(i) is not null then
    str := str || sign || arr(i);

数组置空:

arr(i) := '';
  end if;
  end loop;

去掉前面的标识符:

Result := substr(str, 2, length(str));
  return(Result);
end MyReplace;