问题:在处理一般的数据记录中,对于数字类型的字段,在oracle的排序中,默认把null值做为大于任何数字的类型,当然对于varchar2类型的字段,默认也是该处理方式,但是客户要求排序的过程中,需要把null的字段默认排在前边(从小-->大)。一般的order by xxxx,无法解决。
问题解决:
示例如下:
select * from
(select a.*,rownum as my_sys_rownum from (
select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl (ZBTS, '0'),
nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),
nvl(ADDRESS,' '),BDZID from V_BDZ where rownum<2000
and ZBRL is null
) a
union
select b.*,rownum+(select count(*) from (
select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl(ZBTS, '0'),
nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl (RUNSTATEDES,' '),
nvl(ADDRESS,' '),BDZID from V_BDZ where rownum<2000
and ZBRL is null
)) as my_sys_rownum from (
select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,
nvl(ZBTS, '0'),nvl(FZR,'0'),
nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),
nvl(ADDRESS,' '),BDZID from V_BDZ where rownum<2000
and ZBRL is not null order by ZBRL
) b
)
order by my_sys_rownum desc | |