10 从0 到 n 之间 的数中 1 的位数 总数 （五）

论坛帖：，看谁的快   实现

#include<stdio.h>

unsigned int count = 0;
void judge_1(unsigned int data) //递归，从 高位到低位
{
    if(data != 0)
    {
        judge_1(data / 10);
        if(data == 1)
            count++;
    }
//    printf("count=%u\n",count);
}

void process(unsigned int n)
{
    while(n)
    {
        judge_1(n);
        n--;
    }
    printf("\ncount=%u\n",count);
}

int main()
{
    unsigned int i = 13;
    judge_1(i);
    process(i);

    return 0;
}