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#!/bin/bash
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LIMIT=19 # Upper limit
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echo
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echo "Printing Numbers 1 through 20 (but not 3 and 11)."
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a=0
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while [ $a -le "$LIMIT" ]
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do
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a=$(($a+1))
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if [ "$a" -eq 3 ] || [ "$a" -eq 11 ] # Excludes 3 and 11.
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then
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continue # Skip rest of this particular loop iteration.
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fi
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echo -n "$a " # This will not execute for 3 and 11.
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done
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# Exercise:
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# Why does the loop print up to 20?
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echo; echo
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echo Printing Numbers 1 through 20, but something happens after 2.
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##################################################################
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# Same loop, but substituting 'break' for 'continue'.
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a=0
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while [ "$a" -le "$LIMIT" ]
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do
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a=$(($a+1))
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if [ "$a" -gt 2 ]
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then
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break # Skip entire rest of loop.
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fi
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echo -n "$a "
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done
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echo; echo; echo
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exit 0
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# break 退出本层循环,continue 退出本次循环。
The break command may optionally take a
parameter. A plain break terminates
only the innermost loop in which it is embedded, but a break N breaks out of N levels of loop.
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#!/bin/bash
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# break-levels.sh: Breaking out of loops.
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# "break N" breaks out of N level loops.
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for outerloop in 1 2 3 4 5
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do
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echo -n "Group $outerloop: "
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# --------------------------------------------------------
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for innerloop in 1 2 3 4 5
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do
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echo -n "$innerloop "
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if [ "$innerloop" -eq 3 ]
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then
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break # Try break 2 to see what happens.
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# ("Breaks" out of both inner and outer loops.)
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fi
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done
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# --------------------------------------------------------
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echo
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done
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echo
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exit 0
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#!/bin/bash
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# The "continue N" command, continuing at the Nth level loop.
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for outer in I II III IV V # outer loop
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do
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echo; echo -n "Group $outer: "
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# --------------------------------------------------------------------
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for inner in 1 2 3 4 5 6 7 8 9 10 # inner loop
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do
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if [[ "$inner" -eq 7 && "$outer" = "III" ]]
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then
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continue 2 # Continue at loop on 2nd level, that is "outer loop".
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# Replace above line with a simple "continue"
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# to see normal loop behavior.
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fi
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echo -n "$inner " # 7 8 9 10 will not echo on "Group III."
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done
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# --------------------------------------------------------------------
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done
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echo; echo
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# Exercise:
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# Come up with a meaningful use for "continue N" in a script.
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exit 0
continue N : 可以直接在内层对外层循环控制。进行一下
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# Albert Reiner gives an example of how to use "continue N":
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# ---------------------------------------------------------
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# Suppose I have a large number of jobs that need to be run, with
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#+ any data that is to be treated in files of a given name pattern
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#+ in a directory. There are several machines that access
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#+ this directory, and I want to distribute the work over these
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#+ different boxen.
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# Then I usually nohup something like the following on every box:
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while true
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do
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for n in .iso.*
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do
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[ "$n" = ".iso.opts" ] && continue
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beta=${n#.iso.}
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[ -r .Iso.$beta ] && continue
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[ -r .lock.$beta ] && sleep 10 && continue
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lockfile -r0 .lock.$beta || continue
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echo -n "$beta: " `date`
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run-isotherm $beta
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date
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ls -alF .Iso.$beta
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[ -r .Iso.$beta ] && rm -f .lock.$beta
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continue 2
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done
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break
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done
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exit 0
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# The details, in particular the sleep N, are particular to my
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#+ application, but the general pattern is:
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while true
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do
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for job in {pattern}
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do
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{job already done or running} && continue
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{mark job as running, do job, mark job as done}
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continue 2
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done
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break # Or something like `sleep 600' to avoid termination.
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done
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# This way the script will stop only when there are no more jobs to do
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#+ (including jobs that were added during runtime). Through the use
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#+ of appropriate lockfiles it can be run on several machines
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#+ concurrently without duplication of calculations [which run a couple
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#+ of hours in my case, so I really want to avoid this]. Also, as search
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#+ always starts again from the beginning, one can encode priorities in
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#+ the file names. Of course, one could also do this without `continue 2',
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#+ but then one would have to actually check whether or not some job
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#+ was done (so that we should immediately look for the next job) or not
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#+ (in which case we terminate or sleep for a long time before checking
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#+ for a new job).
这个例子保存-- 待用。。。。。。