-
package test.httpclient4;
-
-
import java.io.File;
-
import java.io.IOException;
-
-
import org.apache.http.HttpEntity;
-
import org.apache.http.HttpResponse;
-
import org.apache.http.HttpStatus;
-
import org.apache.http.client.ClientProtocolException;
-
import org.apache.http.client.HttpClient;
-
import org.apache.http.client.methods.HttpPost;
-
import org.apache.http.entity.mime.MultipartEntity;
-
import org.apache.http.entity.mime.content.FileBody;
-
import org.apache.http.entity.mime.content.StringBody;
-
import org.apache.http.impl.client.DefaultHttpClient;
-
import org.apache.http.util.EntityUtils;
-
-
public class SendFile {
-
-
public static void main(String[] args) throws ClientProtocolException,
-
IOException {
-
HttpClient httpclient = new DefaultHttpClient();
-
//请求处理页面
-
HttpPost httppost = new HttpPost(
-
"");
-
//创建待处理的文件
-
FileBody file = new FileBody(new File("d:/22.rar"));
-
//创建待处理的表单域内容文本
-
StringBody descript = new StringBody("0431.la");
-
-
//对请求的表单域进行填充
-
MultipartEntity reqEntity = new MultipartEntity();
-
reqEntity.addPart("file", file);
-
reqEntity.addPart("descript", descript);
-
//设置请求
-
httppost.setEntity(reqEntity);
-
//执行
-
HttpResponse response = httpclient.execute(httppost);
-
//HttpEntity resEntity = response.getEntity();
-
//System.out.println(response.getStatusLine());
-
if(HttpStatus.SC_OK==response.getStatusLine().getStatusCode()){
-
HttpEntity entity = response.getEntity();
-
//显示内容
-
if (entity != null) {
-
System.out.println(EntityUtils.toString(entity));
-
}
-
if (entity != null) {
-
entity.consumeContent();
-
}
-
}
-
}
-
}
这里说明一下 需要一个额外的包,apache 的mime4j 的lib。
阅读(1052) | 评论(0) | 转发(0) |