最大值，最小值以及排序实现

myTable = {7,1,13,6,89,4,56,2,54,6}

-- 获得table中的最小值
function GetMin(theTable)
    myString = "myValue = math.min("
    for index,value in ipairs(theTable) do
        myString = string.format("%s%d%s", myString, value, ",")
    end
    -- 删除字符串后面多余的逗号
    myString = string.sub (myString, 1, string.len(myString) - 1)
    myString = string.format("%s%s", myString, ")")
   -- 加载和运行一个字符串，这里是myValue = math.min...
    loadstring(myString)() --run the chunk
    print(myString) -- see the string
    print(myValue) --see the result
    return myValue
end

function GetMax(theTable)
    myString = "myValue = math.max("
    for index,value in ipairs(theTable) do
        myString = string.format("%s%d%s", myString, value, ",")
    end
    --remove final comma
    myString = string.sub (myString, 1, string.len(myString) - 1)
    myString = string.format("%s%s", myString, ")")
    loadstring(myString)() --run the chunk
    print(myString) -- see the string
    print(myValue) --see the result
    return myValue
end

function Sort(theTable, direction)
    if direction ~= 1 then
        table.sort(theTable)
    else
        function Reverse(a, b)
            if a < b then
                return false
            else
                return true
            end
        end
        table.sort(theTable, Reverse)
    end
end

使用：
-- 从小到大排序
Sort(myTable, 1)
for i=1, table.getn(myTable) do
  print(myTable[i])
end
或者
table.sort(myTable)
for i=1, table.getn(myTable) do
  print(myTable[i])
end

-- 从大到小排序
Sort(myTable, 1)
for i=1, table.getn(myTable) do
  print(myTable[i])
end