各种排序算法的 ruby 实现

 各种排序算法的 ruby 实现

require 'containers/heap' # for heapsort
 

=begin rdoc
This module implements sorting algorithms. Documentation is provided for each algorithm.
=end

module Algorithms::Sort

  # Bubble sort: A very naive sort that keeps swapping elements until the container is sorted.
  # Requirements: Needs to be able to compare elements with <=>, and the [] []= methods should
  # be implemented for the container.
  # Time Complexity: О(n^2)
  # Space Complexity: О(n) total, O(1) auxiliary
  # Stable: Yes
  #
  # Algorithms::Sort.bubble_sort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]

  #冒泡
  def self.bubble_sort(container)
    loop do
      swapped = false
      (container.size-1).times do |i|
        if (container[i] <=> container[i+1]) == 1
          container[i], container[i+1] = container[i+1], container[i] # Swap
          swapped = true
        end
      end
      break unless swapped
    end
    container
  end
 

  # Comb sort: A variation on bubble sort that dramatically improves performance.
  # Source:
  # Requirements: Needs to be able to compare elements with <=>, and the [] []= methods should
  # be implemented for the container.
  # Time Complexity: О(n^2)
  # Space Complexity: О(n) total, O(1) auxiliary
  # Stable: Yes
  #
  # Algorithms::Sort.comb_sort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]

  def self.comb_sort(container)
    container
    gap = container.size
    loop do
      gap = gap * 10/13
      gap = 11 if gap == 9 || gap == 10
      gap = 1 if gap < 1
      swapped = false
      (container.size - gap).times do |i|
        if (container[i] <=> container[i + gap]) == 1
          container[i], container[i+gap] = container[i+gap], container[i] # Swap
          swapped = true
        end
      end
      break if !swapped && gap == 1
    end
    container
  end
 
  # Selection sort: A naive sort that goes through the container and selects the smallest element,
  # putting it at the beginning. Repeat until the end is reached.
  # Requirements: Needs to be able to compare elements with <=>, and the [] []= methods should
  # be implemented for the container.
  # Time Complexity: О(n^2)
  # Space Complexity: О(n) total, O(1) auxiliary
  # Stable: Yes
  #
  # Algorithms::Sort.selection_sort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]
  def self.selection_sort(container)
    0.upto(container.size-1) do |i|
      min = i
      (i+1).upto(container.size-1) do |j|
        min = j if (container[j] <=> container[min]) == -1
      end
      container[i], container[min] = container[min], container[i] # Swap
    end
    container
  end
 
  # Heap sort: Uses a heap (implemented by the Containers module) to sort the collection.
  # Requirements: Needs to be able to compare elements with <=>
  # Time Complexity: О(n^2)
  # Space Complexity: О(n) total, O(1) auxiliary
  # Stable: Yes
  #
  # Algorithms::Sort.heapsort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]
  def self.heapsort(container)
    heap = Containers::Heap.new(container)
    ary = []
    ary << heap.pop until heap.empty?
    ary
  end
 
  # Insertion sort: Elements are inserted sequentially into the right position.
  # Requirements: Needs to be able to compare elements with <=>, and the [] []= methods should
  # be implemented for the container.
  # Time Complexity: О(n^2)
  # Space Complexity: О(n) total, O(1) auxiliary
  # Stable: Yes
  #
  # Algorithms::Sort.insertion_sort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]
  def self.insertion_sort(container)
    return container if container.size < 2
    (1..container.size-1).each do |i|
      value = container[i]
      j = i-1
      while j >= 0 and container[j] > value do
        container[j+1] = container[j]
        j = j-1
      end
      container[j+1] = value
    end
    container
  end
 
  # Shell sort: Similar approach as insertion sort but slightly better.
  # Requirements: Needs to be able to compare elements with <=>, and the [] []= methods should
  # be implemented for the container.
  # Time Complexity: О(n^2)
  # Space Complexity: О(n) total, O(1) auxiliary
  # Stable: Yes
  #
  # Algorithms::Sort.shell_sort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]
  def self.shell_sort(container)
    increment = container.size/2
    while increment > 0 do
      (increment..container.size-1).each do |i|
        temp = container[i]
        j = i
        while j >= increment && container[j - increment] > temp do
          container[j] = container[j-increment]
          j -= increment
        end
        container[j] = temp
      end
      increment = (increment == 2 ? 1 : (increment / 2.2).round)
    end
    container
  end
 
  # Quicksort: A divide-and-conquer sort that recursively partitions a container until it is sorted.
  # Requirements: Container should implement #pop and include the Enumerable module.
  # Time Complexity: О(n log n) average, O(n^2) worst-case
  # Space Complexity: О(n) auxiliary
  # Stable: No
  #
  # Algorithms::Sort.quicksort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]
  # def self.quicksort(container)
  # return [] if container.empty?
  #
  # x, *xs = container
  #
  # quicksort(xs.select { |i| i < x }) + [x] + quicksort(xs.select { |i| i >= x })
  # end
 
  def self.partition(data, left, right)
    pivot = data[front]
    left += 1
 
    while left <= right do
      if data[frontUnknown] < pivot
        back += 1
        data[frontUnknown], data[back] = data[back], data[frontUnknown] # Swap
      end
 
      frontUnknown += 1
    end
 
    data[front], data[back] = data[back], data[front] # Swap
    back
  end
 
 
  # def self.quicksort(container, left = 0, right = container.size - 1)
  # if left < right
  # middle = partition(container, left, right)
  # quicksort(container, left, middle - 1)
  # quicksort(container, middle + 1, right)
  # end
  # end
 
  def self.quicksort(container)
    bottom, top = [], []
    top[0] = 0
    bottom[0] = container.size
    i = 0
    while i >= 0 do
      l = top[i]
      r = bottom[i] - 1;
      if l < r
        pivot = container[l]
        while l < r do
          r -= 1 while (container[r] >= pivot && l < r)
          if (l < r)
            container[l] = container[r]
            l += 1
          end
          l += 1 while (container[l] <= pivot && l < r)
          if (l < r)
            container[r] = container[l]
            r -= 1
          end
        end
        container[l] = pivot
        top[i+1] = l + 1
        bottom[i+1] = bottom[i]
        bottom[i] = l
        i += 1
      else
        i -= 1
      end
    end
    container
  end
 
  # Mergesort: A stable divide-and-conquer sort that sorts small chunks of the container and then merges them together.
  # Returns an array of the sorted elements.
  # Requirements: Container should implement []
  # Time Complexity: О(n log n) average and worst-case
  # Space Complexity: О(n) auxiliary
  # Stable: Yes
  #
  # Algorithms::Sort.mergesort [5, 4, 3, 1, 2] => [1, 2, 3, 4, 5]
  def self.mergesort(container)
    return container if container.size <= 1
    mid = container.size / 2
    left = container[0...mid]
    right = container[mid...container.size]
    merge(mergesort(left), mergesort(right))
  end
 
  def self.merge(left, right)
    sorted = []
    until left.empty? or right.empty?
      left.first <= right.first ? sorted << left.shift : sorted << right.shift
    end
    sorted + left + right
  end
 
end